The correct answer is “**Option 3**“. Therefore, the number of bit sequences of length 8 that either start with 1 or end with 00 is 160.

Contents

- How many bit strings of length eight are there that end with the two bits 00?
- How many bit strings of length 8 either start with 01 or end with 01?
- How many bit strings are there of length 8?
- How many eight bit strings begin or end with 1?
- How many bit strings of length 10 either start with a 1 bit or end with two bits 00?
- How many strings of length 8 either begin with 3 zeros or end with 4 ones?
- How many strings exists of length 8 either start with 1 or end with 00?
- How many bit strings of length seven either start with a 1 bit or end with the bit 1?
- How many eight bit strings begins either with a 101 or 111?
- How many bit strings of length 10 start with a 1 or end with a 1?
- How many bit strings of length 7 either begin with 00 or end with 111?
- What is an 8 bit string?
- How many eight-bit strings have either the second or fourth bit 1 or both )?
- How many binary strings of length 8 are there that contain two or fewer 1s?
- How many bit strings of length n where n is a positive integer start and end with 1s?

Number of 8-bit strings ending in 00: 26 = **64**.

With this condition, only strings ending in 01 satisfy the required condition. This leaves only 5 binary digits freely selectable: We count them all in the form 0xxxxx01. So there are **25** strings in this sentence.

How many bit sequences are there with length 8? There are 28, so **256**. This means that there are 256 different values you can store in a byte, since a byte consists of eight bits.

How many 8-bit strings start and end with 1? Answer : **2 ^{6}** since the first and last bit are already fixed. How many 8-bit strings have either the second or fourth bit 1 (or both)?

The correct answer is: C

Since 1 bit is fixed, we have 9 positions left, the bits used are 2(0&1). So the total possible strings are **2 ^{9}**.

So in total n1=6⋅25, but here you have 8 ways to get 4 consecutive 1s. Same way for case 2. n2 will be 5⋅24 and again we can find 8 ways to get 3 consecutive 0s. So in total =n1+n2−(8+8)=272−16=**256**.

The correct answer is “**Option 3**“. Therefore, the number of bit sequences of length 8 that either start with 1 or end with 00 is 160.

So the correct answer is **44**.

Therefore, the number of 8-bit strings beginning with either “111…” or “101…” is **64**.

We’re asked for 10 bits, but the first and last bits are already selected for us. Bits are either 1 or 0 so there are 2 choices per bit and 8 bits to choose from. Therefore, there are **28 = 256 bits** strings of length ten that start and end with a 1.

Answer: Using the inclusion-exclusion principle: A = set of 7-bit strings starting with 00 B = set of 7-bit strings ending with 111 The answer is |A∪B| = |A|+|B|-|A∩B|=25+24-22 = **44**.

**A byte** is a string of 8 bits.

Since there are 256 8-bit strings, 64 of which strings do not have 1s in the second and fourth places, 256 − 64 = **192** 256-64=192 256−64=192 strings have a 1 on the second or fourth digit (or both).

Hence, there are **37** binary strings.

How many bit sequences of length n, where n is a positive integer, begin and end with 1? Solution. There are n − 2 slots available (the first and last are occupied by 1), so this must be the same number as the number of bit strings of length n − 2, i.e. **2n−2** .< /p>

- https://www.inf.ed.ac.uk/teaching/courses/dmmr/slides/14-15/Ch6.pdf
- https://math.stackexchange.com/questions/1825199/how-many-bit-strings-of-length-8-start-with-1-or-end-with-01
- http://aleph0.clarku.edu/~djoyce/ma114/Sec51.pdf
- https://condor.depaul.edu/ichu/csc415/notes/notes5/examples5.html
- https://selfstudy365.com/qa/how-many-bit-strings-of-length-ten-either-start-with-a-1-bit-or-end-wi-5e70985af60d5d1807e382a1
- https://math.stackexchange.com/questions/922659/number-of-binary-strings-of-length-8-that-contain-either-three-consecutive-0s-or
- https://testbook.com/question-answer/the-number-of-bit-strings-of-length-8-that-will-ei–6076c6538d78f0dafdbd7063
- https://math.stackexchange.com/questions/757111/how-many-bit-strings-of-length-7-either-begin-with-two-1s-or-end-with-three
- https://testbook.com/question-answer/the-number-of-8-bit-strings-that-can-be-formed-beg–616f9caece2fd4a46e094f9a
- http://courses.ics.hawaii.edu/ReviewICS141/morea/counting/CountingBasics-QA.pdf
- https://www.cs.umb.edu/~duc/www/teaching/cs320/t3_sol.pdf
- https://heather.cs.ucdavis.edu/~matloff/UnixAndC/CLanguage/Bits.html
- https://quizlet.com/explanations/questions/how-many-eight-bit-strings-have-either-the-second-or-the-fourth-bit-1-or-both-7170d841-bc3f7081-bb71-417a-9d9b-6df2a688ba4c
- https://math.stackexchange.com/questions/4360711/how-many-binary-strings-of-length-8-are-there-that-contain-two-or-fewer-1s
- https://www.math.drexel.edu/~dmitryk/Teaching/MATH221-SPRING’12/Quiz8_solutions.pdf

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